Factoring Quadratic Equations when a = 1
Where a, b, and c are constants and a ≠ 0. In other words there must be a x2 term.
Some examples are:
x2 + 3x - 3 = 0
4x2 + 9 = 0 (Where b = 0)
x2 + 5x = 0 (where c = 0)
One way to solve a quadratic equation is by factoring the trinomial.
This part will focus on factoring a quadratic when a, the x2-coefficient, is 1.
Let's solve the following equation by factoring the trinomial:
Step 1: Write the equation in the general form ax2 + bx + c = 0. This equation is already in the proper form where a = 1, b = 5 and c = -14. |
1x2 + 5x - 14 = 0 |
Step 2: Determine the factor pair of c that will add to give b.
2.1: List the factor pairs of c. First ask yourself what are the factors pairs of c, ignoring the negative sign for now. 2.2: Determine the signs of the factors. If c is positive then both factors will be positive or both factors will be negative. If c is negative then one factor will be positive and the other negative. Now create factor pairs 2.3: Determine the factor pair that will add to give b. If both c and b are positive, both factors will be positive. If both c and b are negative, the larger factor will be negative and the smaller will be positive. If c is positive and b is negative, both factors will be negative. If c is negative and b is positive, the larger factor will be positive and the smaller will be negative. |
(1, 14); (2, 7)
This pair does not work.
This pair works!!! (7, -2) |
Step 3: Create two sets of parentheses each containing a x and one of the factors. |
(x + 7)(x - 2) = 0 |
Now that the equation has been factored, solve for x. |
|
Step 4: Set each factor to zero and solve for x. |
(x + 7) = 0, or (x - 2) = 0 x = -7, or x = 2 |
Step 1: Write the equation in the general form ax2 + bx + c = 0. Where a = 1, b = 8 and c = 15. |
x2 + 8x + 15 = 0 |
Step 2: Determine the factor pair of c that will add to give b.
2.1: List the factor pairs of c. First ask yourself what are the factors pairs of c, ignoring the negative sign for now. 2.2: Determine the signs of the factors. If c is positive then both factors will be positive or both factors will be negative. If c is negative then one factor will be positive and the other negative. Now create factor pairs 2.3: Determine the factor pair that will add to give b. If both c and b are positive, both factors will be positive. If both c and b are negative, the larger factor will be negative and the smaller will be positive. If c is positive and b is negative, both factors will be negative. If c is negative and b is positive, the larger factor will be positive and the smaller will be negative. |
(1, 15);(3,5)
This pair does not work.
This pair works!!! (3, 5) |
Step 3: Create two sets of parentheses each containing a x and one of the factors. |
(x + 3)(x + 5) |
Now that the equation has been factored, solve for x. |
|
Step 4: Set each factor to zero and solve for x. |
(x + 3) = 0, or (x + 5) = 0 x= -3, or x = -5 |
Step 1: Write the equation in the general form ax2 + bx + c = 0. Where a = 1, b = 10 and c = -24. |
x2 + 10x - 24 = 0 |
Step 2: Determine the factor pair of c that will add to give b.
2.1: List the factor pairs of c. First ask yourself what are the factors pairs of c, ignoring the negative sign for now. 2.2: Determine the signs of the factors. If c is positive then both factors will be positive or both factors will be negative. If c is negative then one factor will be positive and the other negative. Now create factor pairs 2.3: Determine the factor pair that will add to give b. If both c and b are positive, both factors will be positive. If both c and b are negative, the larger factor will be negative and the smaller will be positive. If c is positive and b is negative, both factors will be negative. If c is negative and b is positive, the larger factor will be positive and the smaller will be negative. |
(1, 24);(2, 12);(3, 8);(6, 4)
These pairs do not work.
This pair works!!! (-2, 12) |
Step 3: Create two sets of parentheses each containing a x and one of the factors. |
(x - 2)(x + 12) |
Now that the equation has been factored, solve for x. |
|
Step 4: Set each factor to zero and solve for x. |
(x - 2) = 0, or (x + 12) = 0 x = 2, or x = -12 |
Related Links: Math algebra Factoring Quadratic Equations when a ≠ 1 Quadratic Formula Algebra Topics |
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