# Rydberg Formula

If the state of an electron in a hydrogen atom is slightly perturbed, then the electron can make a transition to another stationary. The transition will emit a photon with a certain wavelength. If the electron state is characterized by the quantum number n the wavelength is given by the Rydberg formula.

(1/wavelength of the emitted photon) = (Rydberg constant)(1/(integer 1)^{2} - 1/(integer 2)^{2})

The equation is:

1/λ = R(1/(n_{1})^{2} -1/(n_{2})^{2})

with n_{1} < n_{2}

Where:

R: Rydberg's constant (R=1.097 * 10^{7} m^{(−1)})

λ: Wavelength of the emitted photon

n_{1}: integer 1

n_{2}: integer 2

Rydberg Formula Questions:

1) Assume an electron transition occurs from the n_{1}=2 to the n_{2}=3, what is the wavelength of the emitted photon?

Answer:

Substituting the data in the Rydberg formula

1/λ = (1.097 * 10^{7} m^{(−1)})*(1/2 - 1/3)

1/λ = (1.097 * 10^{7} m^{(−1)})*0.1666 = 0.182 *10^{7} (1/m)

λ = 5.47 * 10^{(-7)} m

2) Assume an electron transition occurs from the n_{1}=1and the wavelength of the emitted photon is 1.7 * 10^{(-7)} m, what is the integer number associated with the transition?

Answer:

Substituting the data in the Rydberg formula

1/1.7 * 10^{(-7)} m = (1.097 * 10^{7} m^{(−1)})*(1- 1/n)

From this formula we find n

0.64 = 1 - 1/n

=1 - 0.64

=0.46

=1/0.46

=2.15

n ≈ 2

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