# Charles' Law Formula

Charles' Law shows the relationship between the Temperature and Volume of a gas. Temperature and volume have a direct relationship, so if the volume goes up then the temperature goes up and if the temperature goes down then the volume goes down (and vice versa)

The equation for Charles' is:

*T _{1}* = Initial Temperature (

*Kelvin - K*)

*V _{1}* = Initial Volume (

*L or mL*)

*T _{2}* = Final Temperature (

*Kelvin - K*)

*V _{2}* = Final Volume (

*L or mL*)

*Note*: Temperature must be in Kelvin for the equation to work. You calculate Kelvin temperature by adding 273 to the Celsius temperature.

Charles' Law Formula Questions:

1.) Calculate the decrease in temperature when 2.00 L at 20.0 °C is compressed to 1.00 L.

Answer: For this problem the Initial Volume is *V _{1}* = 2.00

*L*. The Initial Temperature is

*T*= 20.0 + 273 = 293

_{1}*K*. The Final Volume is

*V*= 1.00 L and the Final Temperature (

_{2}*T*) is what you are asked to solve for.

_{2}Plug into the Charles' Law Equation

*T _{2}* = 146.5

*K*

The temperature decreased to 146.5 K.

2.) At 27.00 °C a gas has a volume of 6.00 L. What will the volume be at 150.0 °C

Answer: The Initial Volume is *V _{1}* = 6.00

*L*. The Initial Temperature is

*T*= 27.00 + 273 = 300

_{1}*K*. The Final Temperature is

*T*= 150.0 + 273 = 423

_{2}*K*. The Final Volume (

*V*) is what we are trying to find in the problem.

_{2}Plug into the Charles' Law Equation

*V _{2}* = 8.46

*L*

The volume of the container would be 8.46 *L*.